w^2+7w-638=0

Solution for w^2+7w-638=0 equation:

w^2+7w-638=0

a = 1; b = 7; c = -638;
Δ = b2-4ac
Δ = 72-4·1·(-638)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-51}{2*1}=\frac{-58}{2}
=-29
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+51}{2*1}=\frac{44}{2}
=22
$